Ingo
Hi,
the following code:
template< typename objectT
, typename worldT >
void(objectT::* getInvocationFunctionFor( objectT* v ))(worldT&)
{
return &(objectT::custom_func/*<worldT>*/);
}
will work unless I activate the commented template arg.
Only exception is VC++, but GCC 4.x and Comeau won't take it.
I would like to know, whether there is a good reason for making this
illegal and whether somebody knows a nice workaround. Or did I do
something stupid here?
Ingo
Oct 19 '08 #1
3 
2503 
acehreli
On Oct 19, 2:29*pm, Ingo <Ingo.Nol...@recurdyn.dewrote:
template< typename objectT
* * * * * * * * * * * * * * * * , typename worldT >
void(objectT::* getInvocationFunctionFor( objectT* v ))(worldT&)
{
* * * * return &(objectT::custom_func/*<worldT>*/);}
I recommend using typedef's to make the code readable. I can only fool
myself to think what the return type possibly is. Still, your problem
may be that you are missing a 'template' keyword as in:
return &(objectT::template custom_func<worldT>);
Without that, the compiler would take '<' as the "less than" operator.
Ali
Oct 19 '08 #2
Ingo
>
I recommend using typedef's to make the code readable. I can only fool
myself to think what the return type possibly is. Still, your problem
Could you tell me how to do that??
The return type is a pointer to a member function. The argument of
that member function depends on functions actual template arguments.
Since there is no templated typedef, how would you use a typedef in
this situation?
may be that you are missing a 'template' keyword as in:* *return &(objectT::template custom_func<worldT>);
Without that, the compiler would take '<' as the "less than" operator.
Thank you,
this did it. Should have been obvious to me. I just spend too much
time coding with vc.
Ingo
Ali
Oct 20 '08 #3
Hendrik Schober
Ingo wrote:
>I recommend using typedef's to make the code readable. I can only fool
myself to think what the return type possibly is. Still, your problem
Could you tell me how to do that??The return type is a pointer to a member function. The argument of
that member function depends on functions actual template arguments.
Since there is no templated typedef, how would you use a typedef in
this situation?
The common workaround is to use a traits class.
[...]
Schobi
Oct 20 '08 #4
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